# The invisible rod

Challenge: How can you make a quartz rod invisible with some water, sugar and a beaker?

$n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})$
So you might imagine that if we can change the rod, or the liquid itself, so that light entering from behind the beaker does not refract further on entering the quartz rod, we can effectively make the quartz rod invisible. To do this we want to match up the refractive indices ($n_{1}, n_2$).